How much heat must be absorbed by ice of mass m  = 700 gm at −15° C to take it to the liquid state at 10° C ?

Given parameters. Specific heat of ice (15°C) = 2220 J/kg. K, water = 4187 J/kg.K , water = 4187 J/kg.K Heat of fusion of water = 333 KJ / kg 

1
233kJ Approx
2
30 kJ Approx
3
286 kJ Appro
4
256 kJ Approx 

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