If 'n' number of bolts (made of material with shear stress 's') are subjected to a shear load of 'S', then the diameter of the bolt is given as:

1
\(\sqrt{\frac{4S}{\pi sn}}\)
2
\(\sqrt{\frac{Sn}{4 \pi sn }}\)
3
\(\sqrt{\frac{4\pi S}{ sn}}\)
4
\(\sqrt{\frac{4s}{\pi Sn}}\)

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