A mass ‘m’ of a perfect gas at pressure P1 and volume V1 undergoes an isothermal process. The final pressure is P2 and volume V2. The work done on the system is considered positive. If R is the gas constant and T is the temperature, then the work done in the process is
1
\({P_1}{V_1}\ln \frac{{{V_2}}}{{{V_1}}}\)
2
\( - {P_1}{V_1}\ln \frac{{{P_1}}}{{{P_2}}}\)
3
\(RT\ln \frac{{{V_2}}}{{{V_1}}}\)
4
\( - mRT\ln \frac{{{P_2}}}{{{P_1}}}\)