What would be yielded after simplifying the following Boolean expression:

Y = \(\rm\overline{(A+\bar{B}+C)+(B+\bar{C})}\)

1
Y = (A̅BC̅) + (B̅C)
2
Y = (A̅ + B + C̅) (B̅ + C)
3
Y = 0
4
Y = 1

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