The state of stress for a part undergoing plastic deformation is given as,

\(\sigma = \left[ {\begin{array}{*{20}{c}} {12}&5&0\\ 5&{22}&0\\ 0&0&{ - 12} \end{array}} \right]\;MPa\)

If μ = 0.25 and E = 200 GPa, then distortion energy per unit volume is ______ J/m3

1
1829.44
2
1982.68
3
2064.58
4
2106.74

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