A copper rod with initial length l0 is pulled by a force. The instantaneous length of the rod is given by \(l = {l_0}\left( {1 + 2{e^{4t}}} \right)\) where t represents time. True strain rate at t = 0 is:

1
\(\frac{1}{3}\)
2
\(\frac{8}{3}\)
3
\(\frac{4}{3}\)
4
\(\frac{2}{3}\)

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