A definite double integral is given below, then, evaluation of the double integral over the region R will be __

\(I = \;\mathop \smallint \nolimits_{x\; = \;0}^{x\; = \;r} \mathop \smallint \nolimits_{y\; = \;0}^{\sqrt {{r^2} - {x^2}} } \left( {y{r^2}} \right)\;dx.dy\)

Where R is the region on X - Y plane for the function given as, \(y = \sqrt {{r^2} - {x^2}} \) and r ∈ [0, 5] 

Enter numerical value using the virtual keypad. Round off where necessary.

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