A 18 cm diameter cane has 18 cm of water, overlaid with 15 cm of oil (\(\rho = 891\;\frac{{kg}}{{{m^3}}}\)). It is rotated about the centre in rigid-body motion at 150 RPM as shown in the figure given below. Then,
1
The rise in the liquid level \(\Delta h = 10.186\;cm\)
2
The rise in the liquid level \(\Delta h = 9.175\;cm\)
3
The fluid pressure at the bottom = 4076.204 Pa (Guage)
4
The fluid pressure at the bottom = 4964.217 Pa (Guage)