For the circuit shown in Fig., the equivalent inductance seen at terminals A and B is _______.

1
\({L_{eq}} = {L_1} - \frac{{{M^2}}}{{{L_2}}}\)
2
\({L_{eq}} = {L_2} + \frac{{{M^2}}}{{{L_1}}}\)
3
\({L_{eq}} = {L_1} + \frac{{{M^2}}}{{{L_2}}}\)
4
\({L_{eq}} = {L_2} - \frac{{{M^2}}}{{{L_1}}}\)
5
\({L_{eq}} = {L_2} - \frac{{{L_1}}}{{{M^2}}}\)

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