General solution of the equation (x3 + 3xy2)dx + (3x2y + y3)dy = 0 is (c is a constant)

1
\(\frac{1}{4}\left( {{x^4} + 6{x^2}{y^2} + {y^4}} \right) =c\)
2
\(\frac{1}{5}\left( {8{x^4} + 6{x^3}y + {y^3}} \right) =c\)
3
\(\frac{1}{{12}}\left( {{x^3} + 6x{y^2} + {y^4}} \right) =c\)
4

(x2 + y2) = c

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