Consider the differential equation:
\(\rm 2\dfrac{\mathrm{d^2y} }{\mathrm{d} t^2} +8y=0\) 
With initial conditions:
At t = 0, y = 0 and \(\dfrac{\mathrm{dy} }{\mathrm{d} t}=10\) . The value of y (up to two decimal places) at t = 1 is _______.