A variable has Poisson distribution with mean m. The probability that the variable takes any of the values 0 or 2 is

1

\({e^{ - m}}(1 + m + \frac{{{m^2}}}{{2!}})\)

2

\({e^m}{(1 + m)^{ - 3/2}}\)

3

\({e^{3/2}}{(1 + {m^2})^{ - 1/2}}\)

4

\({e^{ - m}}(1 + \frac{{{m^2}}}{{2!}})\)

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