engineering recuitment GATE CSE 2023-24 Test Series Engineering Mathematics Linear Algebra Matrix Algebra
Let \(M = \;\left[ {\begin{array}{*{20}{c}} 6&3\\ 2&8 \end{array}} \right];\;and\;{M^{ - 1}} = \;\left[ {\begin{array}{*{20}{c}} x&{\frac{{ - 1}}{{14}}}\\ { - \frac{1}{{21}}}&y \end{array}} \right]\)
Then x – y
1
\(\frac{{ - 1}}{{21}}\)
2
\(\frac{1}{{14}}\)
3
\(\frac{1}{{21}}\)
4
\(\frac{1}{7}\)