If 2A + 3B = \(\left[ {\begin{array}{*{20}{c}} 2&{ - 1}&4\\ 3&2&5 \end{array}} \right]\) and A + 2B = \(\left[ {\begin{array}{*{20}{c}} 5&0&3\\ 1&6&2 \end{array}} \right]\), then B =
1
\(\left[ {\begin{array}{*{20}{c}} 8&{ - 1}&2\\ { - 1}&{10}&{ - 1} \end{array}} \right]\)
2
\(\left[ {\begin{array}{*{20}{c}} 8&1&2\\ { - 1}&{10}&{ - 1} \end{array}} \right]\)
3
\(\left[ {\begin{array}{*{20}{c}} 8&1&{ - 2}\\ { - 1}&{10}&{ - 1} \end{array}} \right]\)
4
\(\left[ {\begin{array}{*{20}{c}} 8&1&{ 2}\\ { 1}&{10}&{ 1} \end{array}} \right]\)