Which of the following option is/are true?
1
A schedule has no cycle in the precedence graph then that schedule is conflict serializable and views serializable.
2
A schedule has no cycle in precedence graph then that schedule is not conflict serializable and not view serializable.
3
A schedule has cycled in the precedence graph and if no blind write(R-W) occurs then that schedule does not conflict with serializable and not view serializable.
4
A schedule has cycled in the precedence graph and if no blind write(R-W) occurs then that schedule is conflict serializable and view serializable.