If \(\frac{x}{x+1}+\frac{y}{y+1}+\frac{z}{z+1}=a\) so, then the value of \(\frac{1}{x+1}+\frac{1}{y+1}+\frac{1}{z+1}\) (x, y, z are real numbers) will be

1
3 - a
2
a + 2
3
a
4
> a

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