Let the number of fringes on the reference block be N over a width of l mm. If the distance between two slip gauges is L and λ is wavelength, then the difference in height of slip gauges (h) is,

1
\(\frac{LN}{2l\lambda}\)
2
\(\frac{\lambda l}{2L}\)
3
\(\frac{\lambda LN}{2l}\)
4
\(\frac{2\lambda lN}{L}\)

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