The iterative formula to find √N using newton-raphson method is

1
xn+1 = xn(2 – Nxn)
2
\({x_{n + 1}} = \frac{1}{2}\left( {{x_n} + \frac{N}{{{x_n}}}} \right)\)
3
\({x_{n + 1}} = \frac{1}{2}\left( {{x_n} + \frac{1}{{N{x_n}}}} \right)\)
4
xn+1 = xn (2 + Nxn)

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