The solution of the initial value problem \(\frac{{{\rm{dy}}}}{{{\rm{dx}}}} = - 2{\rm{xy}};{\rm{y}}\left( 0 \right) = 2\) is 

1
\(1 + {{\rm{e}}^{ - {{\rm{x}}^2}}}\)
2
\(2{{\rm{e}}^{ - {{\rm{x}}^2}}}\)
3
\(1 + {{\rm{e}}^{{{\rm{x}}^2}}}\)
4
\(2{{\rm{e}}^{{{\rm{x}}^2}}}\)

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