The compound statement (∼(P ∧ Q)) ∨ ((∼ P) ∧ Q) ⇒ ((∼ P) ∧ (∼ Q)) is equivalent to

1
(∼ Q) ∨ P
2
((∼ P) ∨ Q) ∧ (∼ Q)
3
(∼ P) ∨ Q
4
((∼ P) ∨ Q) ∧ ((∼ Q) ∨ P)

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