engineering recuitment NIELIT Scientific Assistant Mock Test 2025 Mathematics Relations and Functions Special Functions
The logarithm of \(\dfrac{1}{256}\) to the base \(2\sqrt{2}\) is:
1
\(\dfrac{8}{3}\)
2
\(\dfrac{-16}{3}\)
3
\(\dfrac{-14}{3}\)
4
\(\dfrac{-8}{3}\)