If \(a = \;\frac{{\sqrt {3\;} + \;\sqrt 2 }}{{\sqrt 3 \; - \;\sqrt 2 }}\) and \(b = \;\frac{{\sqrt 3 \; - \;\sqrt 2 }}{{\sqrt 3 \; + \;\sqrt 2 }}\), then find the value of \(\frac{{a + b}}{{a - b}} - \;\frac{{a - b}}{{a + b}}\)

1
\(\frac{1}{{\sqrt 6 }}\)
2
\(10\sqrt 6 \)
3
\(\frac{1}{{10\sqrt 6 }}\)
4
1

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