If 3(sec2θ  + tan2θ) = 5, 0° < θ < 90°, then the value of cosec θ is:

1
\(\dfrac{1}{2}\)
2
\(\dfrac{1}{\sqrt3}\)
3
2
4
\(\dfrac{2\sqrt3}{3}\)

Sponsored

hivanix.in

Visit

This quiz is brought to you by hivanix.in

🌐 Web App Development

Quick Navigation