Find the inductor current after the switch closes in the circuit.
1
\(i\left( t \right) = 4\;\left( {1 + {e^{ - \frac{t}{5}}}} \right)\) mA, and t is in μs
2
\(i\left( t \right) = 4\;\left( {1 + {e^{ \frac{t}{5}}}} \right)\)mA, and t is in μs
3
\(i\left( t \right) = 4\;\left( {1 - {e^{ - \frac{t}{5}}}} \right)\) mA, and t is in μs
4
\(i\left( t \right) = 4\;\left( {1 - {e^{ \frac{t}{5}}}} \right)\) mA, and t is in μs