Inverse Laplace transform of \(F\left( s \right) = \frac{{\left( {s + 2} \right)}}{{s\left( {s + 3} \right)\left( {s + 4} \right)}}\) would be

1
(1/6) + (1/3e-3t) + (1/2e4t)
2
(1/6) – (1/3e-3t) + (1/2e-4t)
3
(1-3e-3t) + (1/2e4t)
4
(1/6) + (1/3e-3t) – (1/2e-4t)

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