If A, B and C are any 3 events such that \(P\left( A \right) = P\left( B \right) = P\left( C \right) = \frac{1}{4}\)

\(P\left( {A \cap B} \right) = P\left( {B \cap C} \right) = 0;\;\;P\left( {C \cap A} \right) = \frac{1}{8}\)

Find the probability that at least one of the events A, B and C occurs.

1
\(\frac{3}{8}\)
2
\(\frac{7}{8}\)
3
\(\frac{1}{8}\)
4
\(\frac{5}{8}\)

Sponsored

hivanix.in

Visit

This quiz is brought to you by hivanix.in

🌐 Web App Development

Quick Navigation