A class has 10 boys and 5 girls. 3 students are selected at random one after the other. The probability that the 1st and the 3rd are of the same gender and the 2nd is of the opposite gender is:

1
\(\frac{4}{21}\)
2
\(\frac{8}{21}\)
3
\(\frac{2}{21}\)
4
\(\frac{5}{21}\)

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