Two circles, each of radius r, with centres P and Q, are such that each circle passes through the centre of the other circle. Then the area common to the circles is less than one-third of the sum of the areas of the two circles by

1
\(\frac{\sqrt{3}r^2}{4}\)
2
\(\frac{\sqrt{3}r^2}{3}\)
3
\(\frac{\sqrt{3}r^2}{2}\)
4
\(\sqrt{3}r^2\)

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