A continuous beam ABCD had end A as fixed and support B and C are simple supports while end D is free. The fixed end moments for beam AB are FEMAB = -19.2 Nm and FEMBA = 28.8 kNm. The moment equation for slope deflection method for beam AB can be written as:
1
\(\begin{array}{l} {M_{ab}} = \frac{{2EI}}{L}(2{\theta _A} + {\theta _B}) + 28.8\\ {M_{ba}} = \frac{{2EI}}{L}({\theta _A} + 2{\theta _B}) - 19.2 \end{array}\)
2
\(\begin{array}{l} {M_{ab}} = \frac{{2EI}}{L}({\theta _A} ) - 19.2\\ {M_{ba}} = \frac{4{EI}}{L}({\theta _A} ) + 28.8 \end{array}\)
3
\(\begin{array}{l} {M_{ab}} = \frac{{4EI}}{L}({\theta _A} ) - 19.2\\ {M_{ba}} = \frac{2{EI}}{L}({\theta _A} ) + 28.8 \end{array}\)
4
\(\begin{array}{l} {M_{ab}} = \frac{{2EI}}{L}({\theta _B} ) - 19.2\\ {M_{ba}} = \frac{4{EI}}{L}({\theta _B} ) + 28.8 \end{array}\)