There are two identical small holes of area of cross-section a on the opposite sides of a tank containing a liquid of density \( \rho \). The difference in height between the holes is \( h \). Tank is resting on a smooth horizontal surface. Horizontal force which will has to be applied on the tank to keep it in equilibrium is
1
\( gh\rho a \)
2
\( \frac{2gh}{\rho a} \)
3
\( 2 \rho agh \)
4
\( \frac{\rho gh}{a} \)