If the volume of spherical ball is increasing at the rate of 4π cc/sec then the rate of change of its surface area when the volume is 288π cc is

1
\(\rm \dfrac{4}{3}\pi\ \text{cm}^2/sec\)
2
\(\rm \dfrac{2}{3} \pi \ cm^2/sec\)
3
4 π cm2/sec
4
2 π cm2/sec

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