If P(n) = 2 + 4 + ......+ 2n, n ϵ N, then P(k) = k(k + 1) + 2 ⇒ P(k) = k(k + 1) + 2 for all k ϵ N. S we can conclude that P(n) = n(n + 1) + 2 for

1
all n ϵ N
2
n > 1
3
n > 2
4
nothing can be said

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