If \(\rm f(x)=\left\{\begin{matrix}\rm \dfrac{\sin 3x}{e^{2x}-1}, &\rm x \ne 0\\\rm k-2, &\rm x=0 \end{matrix}\right.\) is continuous at x = 0, then k = ?

1
\(\dfrac{3}{2}\)
2
\(\dfrac{9}{5}\)
3
\(\dfrac{1}{2}\)
4
\(\dfrac{7}{2}\)

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