The distance of the point \( (1, 3, -7) \) from the plane passing through the point \( (1, -1, -1) \), having normal perpendicular to both the lines \( \dfrac{x-1}{1} = \dfrac{y+2}{-2} = \dfrac{x-4}{3} \) and \( \dfrac{x-2}{2} = \dfrac{y+1}{-1} = \dfrac{z+7}{-1} \), is.
1
\( \dfrac{20}{\sqrt{74}} \)
2
\( \dfrac{10}{\sqrt{83}} \)
3
\( \dfrac{5}{\sqrt{83}} \)
4
\( \dfrac{10}{\sqrt{74}} \)