In a room there are eight couples. Out of them if 4 people are selected at random, the probability that they may be couples is

1
\(\frac{{{{\rm{\;}}^8}{{\rm{c}}_4}}}{{{{\rm{\;}}^{16}}{{\rm{c}}_4}}}\)
2
\(\frac{{{{\rm{\;}}^8}{{\rm{c}}_2}}}{{{{\rm{\;}}^{16}}{{\rm{c}}_8}}}\)
3
\(\frac{{{{\rm{\;}}^8}{{\rm{c}}_2}}}{{{{\rm{\;}}^8}{{\rm{c}}_4}}}\)
4
\(\frac{{{{\rm{\;}}^8}{{\rm{c}}_2}}}{{{{\rm{\;}}^{16}}{{\rm{c}}_4}}}\)

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