A particle moving in a circle of radius R with uniform speed takes time T to complete one revolution. If this particle is projected with the same speed at an angle θ to the horizontal, the maximum height attained by it is equal to 4R. The angle of projection θ is then given by :
1
\(\rm \sin^{-1} \left[ \left( \frac{2gT^2}{\pi^2 R} \right) \right]^{\frac{1}{2}}\)
2
\(\rm \sin^{-1} \left[ \left( \frac{\pi^2R}{2gT^2} \right) \right]^{\frac{1}{2}}\)
3
\(\rm \cos^{-1} \left[ \left( \frac{2gT^2}{\pi^2 R} \right) \right]^{\frac{1}{2}}\)
4
\(\rm \cos^{-1} \left[ \left( \frac{\pi R}{2gT^2} \right) \right]^{\frac{1}{2}}\)