Corner points of the feasible region determined by the system of linear constraints are (0, 3), (1, 1), and (3, 0). Let Z = px + qy, where p, q > 0.
Condition on p and q so that the minimum of Z occurs at (3, 0) and (1, 1) is
1
p = 2q
2
p = \(\rm\frac{q}{2}\)
3
p = 3q
4
p = q