Mathematics Three Dimensional Geometry Distance from a Plane

The Cartesian equation of a plane parallel to the plane \(\overline r\) . (2i + 3j - 4k) = 1 and at a distance of 2 units from it is

1
2x + 3y - 4z = 3
2
2x + 3y - 4z = 1 ± \(2\sqrt{29}\)
3
2x + 3y - 4z = -1 ± \(2\sqrt{29}\)
4
2x + 3y - 4z = -3

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