A and B are two students. Their chances of solving a problem correctly are \(\frac{1}{3}\) and \(\frac{1}{4}\), respectively. If the probability of their making a common error is, \(\frac{1}{20}\) and they obtain the same answer, then the probability of their answer to be correct is

1
\(\frac{1}{12}\)
2
\(\frac{1}{40}\)
3
\(\frac{13}{120}\)
4
\(\frac{10}{13}\)

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