If (a, b), (x1, y1) and (x2, y2) are the vertices of a triangle such that the x-coordinates a, x1, x2 are in geometric progression with common ratio r and the y-coordinates b, y1, y2 are also in geometric progression with common ratio s, then the area of the triangle is:

1
\(\dfrac{1}{2}ab(r-1)(s-1)(s-r) \)
2
ab(r - 1)(s - 1)(s - r)
3
\(\dfrac{1}{2}ab(r-1)(s-1)(s+r)\)
4
ab(r - 1)(s - 1)(s + r)

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