The incentre of triangle formed by the lines x = 0, y = 0 and 3x + 4y = 12 is

1
\(\left( {\frac{1}{2},\frac{1}{2}} \right)\)
2
(1,1)
3
\(\left( {1,\frac{1}{2}} \right)\)
4
\(\left( {\frac{{11}}{2},1} \right)\)

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