The filament of an electric bulb draws a current of 0.05 A from a 200 V source. The power of the bulb and the number of electrons (charge = 1.6 x 10-19C) passing through a cross section of the filament in 5 minutes respectively are

1
10 W ; \(\backsimeq\) 9 × 1019
2
100 W ; \(\backsimeq\) 9 × 1019
3
10 W ; \(\backsimeq\) 9 × 1018
4
W ; \(\backsimeq\) 9 × 1018

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