\(\frac{4^k \times 20^{m-1} \times 12^{m-k} \times 15^{k+m}}{16^m \times 9^{m-1} \times 5^{k+2 m}}\) is equal to:

1
\(\frac{9}{80}\)
2
\(\frac{9}{20}\)
3
\(\frac{9}{50}\)
4
\(\frac{9}{40}\)

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