Two ammeters A and B both 0-10 A have an internal resistance of 1 Ω and 0.5 Ω respectively. They are connected in parallel. If the total current is 15 A, then

1
IA = IB = 7.5 A
2
IA = 5 A, IB = 10 A
3
IA = 10 A, IB = 5 A
4
IA = 9 A, IB = 6 A

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