For steady, fully developed flow inside a straight pipe of diameter D, neglecting gravity effects, the pressure drop Δp over a length L and the wall shear stress τw are related by

1
\({\tau _w} = \frac{{{\rm{\Delta }}pD}}{{4L}}\)
2
\({\tau _w} = \frac{\Delta p{D^2}}{4{L^2}}\)
3
\({\tau _w} = \frac{{{\rm{\Delta }}pD}}{{2L}}\)
4
\({\tau _w} = \frac{{4{\rm{\Delta }}pL}}{D}\)

Sponsored

hivanix.in

Visit

This quiz is brought to you by hivanix.in

🌐 Web App Development

Quick Navigation