A particle is projected at an angle θ to the horizontal and it attains a maximum height H. The time taken by the projectile to reach the highest point, of its path is

1
\(\frac{{\sqrt H }}{g}\)
2
\(\sqrt {\frac{{2H}}{g}} \)
3
\(\frac{{\sqrt {2H\sin \theta } }}{g}\)
4
\(\frac{{\sqrt {2H} }}{{\sin \theta }}\)

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