The resistances of the filament of two bulbs are R1 and R2 . If both of these are connected in parallel, then the ratio of loss of power will be
1
\(\rm \frac{R_2}{R_1}\)
2
\(\rm \frac{R_1}{(R_1+R_2)}\)
3
\(\rm \frac{R_2}{(R_1+R_2)}\)
4
\(\rm\frac{R_1}{R_2}\)