What is the inverse Z transform of the given signal?
\(X(Z) \space = \space \frac {(Z-1) \space (Z+0.8)} {(Z-0.5)(Z+0.2)} \space \)
1
8δ[n] - 1.857(0.5)n u[n] + 5.143(-0.2)n u[n]
2
8 + 1.857(0.5)n u[n] - 5.143(-0.2)n u[n]
3
8δ[n] - 1.857(0.5)n u[n] - 5.143(-0.2)n u[n]
4
8δ[n] + 1.857(0.5)n u[n] + 5.143(-0.2)n u[n]