What is the solution of the given difference equation using Z-transform ?
y[n] + 3y[n - 1] + 2y[n - 2] = 2x[n] - x[n - 1]; y[-1] = 0; y[-2] = 1, x[n] = u[n]
1
\(\rm {y[n] = \left( - \dfrac{1}{2}(-1)^{n-1} + \dfrac{4}{3} (-2)^{n-1} + \dfrac{1}{6} \right)u[n - 1]} \space \)
2
\(\rm {y[n] = \left( - \dfrac{1}{2}(-1)^{n-1} + \dfrac{4}{3} (-2)^{n-1} - \dfrac{1}{6} \right)u[n - 1]} \space \)
3
\(\rm {y[n] = \left( - \dfrac{1}{2}(-1)^{n-1} - \dfrac{4}{3} (-2)^{n-1} + \dfrac{1}{6} \right)u[n - 1]} \space \)
4
\(\rm {y[n] = \left( \dfrac{1}{2}(-1)^{n-1} + \dfrac{4}{3} (-2)^{n-1} + \dfrac{1}{6} \right)u[n - 1]} \space \)