\(\sqrt[3]{{cosx - jsinx}}\) is equal to 

1
(cos x)1/3 – j(sinx)1/3
2
\(\sqrt[3]{{{{\cos }^2}x - jsi{n^2}x}}\)
3
\(\cos \frac{{\rm{x}}}{3} - {\rm{jsin}}\frac{{\rm{x}}}{3}\)
4
\(\sin \frac{x}{3} - jcos\frac{x}{3}\)

Sponsored

hivanix.in

Visit

This quiz is brought to you by hivanix.in

🌐 Web App Development

Quick Navigation